Home Puzzles arithmetic – How many digits will be faraway from a division puzzle?

arithmetic – How many digits will be faraway from a division puzzle?

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arithmetic – How many digits will be faraway from a division puzzle?

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You are on the lookout for least proportion, with out regarding with the Difficulty of the puzzle.

In that case, the proportion will be made arbitrarily small.
Here is an instance with 31 digits eliminated:

999)*********(*******
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            0

Here the format AAA)BBB(CCC means AAA is dividing BBB to get the reply as CCC.

We can lengthen the identical arbitrarily, eg right here is the subsequent risk with 43 digits eliminated:

999)************(**********
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       ***
       ***
          ***
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             ***
               0

We now listing the third instance with 55 digits eliminated:

999)***************(*************
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          ***
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                  0

We now listing a fourth instance with 67 digits eliminated:

999)******************(****************
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                     0

Enough Examples, allow us to generalise this, such that 999 Divides a (3N)-Digit quantity with a (3N-2)-Digit quantity as the reply.

Calculating the proportion:

999)************[3N ‘*’ characters](**********[3N-2 ‘*’ characters]

This will include completely (3N)+(3N-2)+(3N)+(3N-3) = 12N-5 ‘*’ characters, when counting all of the rows.

With 4 recognized digits [9,9,9,0] , whole variety of digits = 12N-1.

Percentage of recognized digits = 100*(4)/(12N-1).

We can take N = 100, for instance, to get 0.3%.

We can take N = 1000 to get 0.03%.

EDIT:

Solutions to these puzzles will likely be like this:
The end result Digits will likely be 1001001…001 (1 adopted by 001 (N-1) instances).
All remaining unknown Digits will likely be 9s.

999)999999999(1001001
    999
       999
       999
          999
          999
            0
999)999999999999(1001001001
    999
       999
       999
          999
          999
             999
             999
               0

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