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I’ve solved a variety of Star Battle puzzles, however occasionally a few of them appear a lot tougher than others. This has additionally been famous earlier right here.
It appears as if I’m lacking some method to have the ability to make progress on this one – other than guessing and seeing if that ends in a contradiction afterward.
Can anybody share some perception?
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You can attempt dividing the grid in some helpful style. For instance, for those who have a look at the realm contained in the blue rectangle right here:
You know the realm with the blue border has to have 8 stars. Six of them come from the three rooms absolutely contained in the blue rectangle, highlighted in pink. The rooms highlighted in yellow can have at most one star exterior of the blue border. So to maintain the blue space to a complete of 8 stars, each of the yellow areas should have a star exterior of the blue rectangle. This will get us one step additional, and you may proceed from there:
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For the following step:
Look on the backside 4 rows. Three areas are fully contained in these rows, in order that they contribute 6 stars. Now have a look at the 11-cell area on the suitable facet. It solely has three cells exterior of the underside 4 rows, and they’re configured in order that they will comprise at most one star. This signifies that for the 6-cell area at left, solely certainly one of its cells within the backside 4 rows accommodates a star, so R6C2 should comprise a star as effectively.
You even have some logic to exclude stars:
from R2C6 and R3C8 with the snaky 8-cell area at prime. Each of the remaining 2-cell triominos can solely have one star, so every has one.
One different factor:
Look within the right-most 5 columns. Four areas are fully contained, so the remaining 2 stars have to be in a 6-cell vary: R3C6-R6C6 plus R5C7 and R6C7. The 2×2 sq. within the decrease area then accommodates at most one star, which breaks issues open.
answered 34 minutes in the past
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