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Is it potential to order a whole set of chess items of the identical coloration (8 Pawns, 2 Knights, 2 Bishops, 2 Rook, Queen and King) in such a means that none of them assault one another? If so, how?
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One might make the argument that the 4 pawns on the highest row needs to be promoted, however aside from that, 16 white items with none attacking one another, with correct bishop placement.
answered Oct 14, 2014 at 0:08
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I provide the following:
This answer can come up in an everyday chess sport, the place the black king is superfluous. The situations would nonetheless be met if the black king have been eliminated. White must make 25 strikes (Queenside fortress, due to h34 in feedback) to get into this place, however as a result of want of capturing all opposing items, a sport resulting in this place would in all probability take extra turns.
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Here is an answer that additionally maximizes the variety of pawns on the board. It additionally takes into consideration pawn promotion and the no-pawns-on-first-row rule.
12 Pawns
Ideas used
The space of affect by the rooks is fixed wherever they’re (2 rows and a pair of columns). I positioned the bishops and the knights to the aspect to reduce their space of affect and the rooks on the following columns so the two required by the rooks overlap with many of the squares managed by the knights and bishops.
There are 5 columns remaining at this level and pawns positioned in a column render the columns subsequent to them ineffective. This means the easiest way to position them is to place them on columns 1, 3 and 5. This leaves the Queen on column 2 or 5.
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I offer you this image right here:
All items positioned, bishops on reverse colours, and no pawns on the first or eighth ranks.
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answered 4 hours in the past
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