Does a quadruple pegged after a “go” depend for 12 factors? My neighbor and I had this uncommon state of affairs and we’re unsure if we scored it accurately.

Player A led with a ten.
Player B performed a 5 and pegged two factors for the 15 combo.
Player A performed a 5 and pegged two factors for the pair (20 cumulative pts.).
Player B performed one other 5 and pegged six factors for the three of a form (25 cumulative pts.).

So far so good. The subsequent half is the place we’re confused.
Player A then known as “go.”
Player B performed the fourth 5 and pegged 12 factors for the quadruple, plus some extent for the “go.”

Is that right? Does participant B get six factors for the three of a form then an extra 12 for the quadruple? Is {that a} type of double counting?

Thanks,
David