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Requested
Considered
590 instances
OEEE
XOOX
EXEX
XEOE
Precisely one letter must be exchanged into one of many different two. However the place and which one?
I meant this to be a part of Month-to-month Matter Problem. That is type of a touch.
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I feel it is
The 2nd E within the third row, it must be an O
How come:
The entire grid appears to be like like Tic-tac-toe on a 4×4 grid. Given there are 5 Xs and 4 Os, it must be O’s flip to play. Enjoying within the 2nd empty (E) sq. within the third row ensures a win for the participant with the Os, finishing each a vertical 3 in a row and a diagonal one.
$$ start{array}{cccc} mathsf{textual content{O}} & & & mathsf{textual content{X}}& mathsf{textual content{O}} & mathsf{textual content{O}} & mathsf{textual content{X}} & mathsf{textual content{X}} & colour{lime}{mathsf{textual content{O}}} & mathsf{textual content{X}} mathsf{textual content{X}}& & mathsf{textual content{O}} & finish{array}$$
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Undecided if that is the intention, however
X is current in rows
2,3,4and columns1,2,4
O is current in rows1,2,4and columns1,2,3
E is current in rows1,3,4and columns1,2,3,4
So
If the constraint is
current in 3 rows/columns, the one approach is to alter the E in column 1 (all different columns have 2 Es). Can solely be modified toXto not break constraint for O.
answered 20 hours in the past
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4
Is it
the 2nd E within the 4th row must be an O.
Reasoning:
Tic-tac-toe involves thoughts. There are 5 X’s, however simply 4 O’s, so it appears we have to change one of many E’s to an O, however which one?
The X’s kind 3 rows of two, the place 2 of these rows are linked at one level. Subsequently we should place the O in order that that setup holds true for O’s additionally. Which means the O should exchange one of many E’s on the underside row.
To resolve which one, we discover the variety of columns and rows taken up by X is 3, so with a purpose to match that, the O should exchange the E within the 2nd column.
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1
