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Some normal observations:

- Each 3×3 field accommodates precisely three mines. They cannot be all in a single row, column, or diagonal, since then the $1$ in that field can be unplaceable. If the $3$ in a field is within the nook, then the $1$ should be within the reverse nook. The centre cell of a field can by no means be $1$ or $2$.
- Two different forbidden mixtures of mine placement are ${$top-left, top-middle, middle-left$}$ and ${$top-left, top-middle, bottom-left$}$ (additionally rotations and reflections of those patterns), since then the $2$ in that field can be unplaceable.
- Every mine cell should be at the least $4$, so in Killer Sudoku packing containers or row/column sums, two mines may give a sum from $9$ to $17$ inclusive, three mines from $15$ to $24$ inclusive, 4 mines from $22$ to $30$, 5 mines from $30$ to $35$, six mines should be $39$. Also, if some mine cells sum to $9$, then they should be both a single cell containing $9$ or two cells containing $4,5$, whereas if some mine cells sum to $10$, then they should be two cells containing both $4,6$ or $5,5$.

Of explicit curiosity on this puzzle:

Killer Sudoku Box 14 has two mines ($5,9$ or $6,8$). Column 28 has 4 mines ($4,7,8,9$ or $5,6,8,9$).

Step-by-step deductions

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Start with the Killer Sudoku field summing to $34$.

It can comprise at most 5 mine cells (three from the top-middle field, two from the top-right field), however lower than 5 cannot sum to $34$, so it should be precisely 5. Therefore

allthe mines of the top-middle field should be in that Killer Sudoku field. Then there’s just one potential place for the mine adjoining to the already-placed $1$, and the $3$ should even be in that field. Using pink for mines and gray for not-mines, now we have this, with the numbers inside that 2×2 sq. being $3$ and three of $9,8,7,6,4$ (these being the 5 mine cells summing to $34$).

Also, the Killer Sudoku field summing to $22$.

It can comprise at most 4 mine cells (the decrease three of the 5 cannot all be mines), however lower than three cannot sum to $22$, so it should be three or 4. If it is three, they should be $9,8,5$ or $9,7,6$; if it is 4, they should be $4,5,6,7$.

And the Killer Sudoku field summing to $27$.

By the final observations above about what given numbers of mines can sum to, this field should comprise precisely 4 mines, $4,7,8,9$ or $5,6,8,9$. In the bottom-left and bottom-middle packing containers, that is both three (counting the centre cell) and one, or two and (each) two. Also the 2 cells within the $9$ diagonal cannot each be mines, as a result of if there are two mines on this diagonal they should be $4$ and $5$, which might’t each seem as mines within the $27$ field.

Now think about the row with $32$ sum.

Any row or column can comprise at most six mines. Here among the numbers $4,5,6,7,8,9$ should sum to $32$, so it could solely be the 5 numbers $4,5,6,8,9$. Considering the highest three 3×3 packing containers, two of them will need to have two mines within the center row, and the third will need to have precisely one mine within the center row.

**This continues to be a really partial reply, however it’s a very laborious puzzle!** Maybe another person can proceed from right here, utilizing a few of my methodology and deductions, or I’ll come again later to increase on this.

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